MCQ
The effective current $I$ in the given circuit at very high frequencies will be $.......A$


- A$4$
- ✓$44$
- C$42$
- D$46$

$X _{ C }=\frac{1}{\omega C } \approx 0$
Also $X _{ L }=\omega L \approx \infty$
Thus, equivalent circuit can be redrawn as
$Z =1+2+2=5 \Omega$
$I =\frac{220 V }{5 \Omega}=44 A$
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