The efficiency of a Carnot engine depends upon
NEET 2020, Easy
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Efficiency of Carnot engine
$\eta=\left(1-\frac{T_{2}}{T_{1}}\right) \times 100 \%$
So efficiency depends on temperature of source $\left(T_{1}\right)$ and temperature of $\sin k\left(T_{2}\right)$
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