The elastic limit of brass is $379\,MPa.$ .......... $mm$ should be the minimum diameter of a brass rod if it is to support a $400\,N$ load without exceeding its elastic limit .
A$1$
B$1.16$
C$0.90$
D$1.36$
JEE MAIN 2019, Medium
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B$1.16$
b $\frac{{400}}{{\frac{\pi }{4}{d^2}}} = 379 \times {10^6}$
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