Reason : $I_1 = I_2$ implies that the fields due to the current $I_1$ and $I_2$ will be balanced.
$(1)$ The measured value of $R$ will be $978 \Omega$
$(2)$ The resistance of the Voltmeter will be $100 k \Omega$.
$(3)$ The resistance of the Ammeter will be $0.02 \Omega$ (round off to $2^{\text {nd }}$ decimal place)
$(4)$ If the ideal cell is replaced by a cell having internal resistance of $5 \Omega$ then the measured value of $R$ will be more than $1000 \Omega$.

