The electric current passing through a metallic wire produces heat because of
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(d) Colliding electrons lose their kinetic energy as heat.
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Consider a block of conducting material ofresistivity '$\rho$' shown in the figure. Current '$I$' enters at '$A$' and leaves from '$D$'. We apply superp osition principle to find voltage '$\Delta V$ ' developed between '$B$' and '$C$'. The calculation is done in the following steps:
$(i)$ Take current '$I$' entering from '$A$' and assume it to spread over a hemispherical surface in the block.
$(ii)$ Calculatefield $E(r)$ at distance '$r$' from $A$ by using Ohm's law $E = \rho j$, where j is the current per unit area at '$r$'.
$(iii)$ From the '$r$' dependence of $E(r)$, obtain the potential $V(r)$ at $r$.
$(iv)$ Repeat $(i), (ii)$ and $(iii)$ for current '$I$' leaving '$D$' and superpose results for '$A$' and '$D$'.
For current entering at $A$, the electric field at a distance '$r$'
from $A$ is
The figure shows a circuit diagram of a ‘Wheatstone Bridge’ to measure the resistance $G$ of the galvanometer. The relation $\frac{P}{Q} = \frac{R}{G}$ will be satisfied only when
$32$ cells, each of $emf$ $3V$, are connected in series and kept in a box. Externally, the combination shows an $emf$ of $84\, V$. The number of cells reversed in the combination is
In the shown arrangement of the experiment of the meter bridge if $AC$ corresponding to null deflection of galvanometer is $x$, what would be its value if the radius of the wire $AB$ is doubled