The electric field $\vec E$ between two points is constant in both magnitude and direction. Consider a path of length d at an angle $\theta = 60^o$ with respect to field lines shown in figure. The potential difference between points $1$ and $2$ is
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Points $2$ and $3$ are equipotential points. Hence, potential difference between points $1$ and $2$ is the same as that between $1$ and $3$.

                  $\therefore V = Ed \,cos \,60^o$

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