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STD 12 - 2. Electric potential and capacitance — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - 2. Electric potential and capacitance4 Marks
MCQ
A parallel plate air capacitor is charged to a potential difference of $V$ volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates
  • A
    decreases
  • ✓
    increases
  • C
    does not change
  • D
    becomes zero
✓

Answer

Correct option: B.
increases
b
Capacitance of a parallel plate capacitor

$C=\frac{\varepsilon_{0} A}{d}$     $...(i)$

Also capacitance = potential difference$/$charge     $.....(ii)$

When battery is disconnected and the distance between the plates of the capacitor is increased then capacitance increases and charge remains constant.

since capacitance $=$ potential difference$/$charge

$\therefore$ Potential difference increases.

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