Question
Three point masses $m_1, m_2$ and $m_3$ are placed at the corners of a thin massless rectangular sheet ($1.2 \,m \times$ $1.0 \,m$ ) as shown. Centre of mass will be located at the point ........... $m$
✓
Answer
(c)
$x_{ cm }=\frac{m_1 x_1+m_2 x_2+m_3 x_3}{m_1+m_2+m_3}$
$y_{ cm }=\frac{m_1 y_1+m_2 y_2+m_3 y_3}{m_1+m_2+m_3}$
$x_{ cm }=\frac{(1.6)(0)+(2.4)(0)+2(1.2)}{1.6+2.4+2}=0.4 \,m$
$y_{ cm }=\frac{(1.6)(0)+(2.4) 1+2(0)}{1.6+2.4+2}=0.4 \,m$
$\text { So, }\left(x_{ cm }, y_{ cm }\right)=(0.4,0.4) \,m$
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