MCQ
The electronic configuration of the outermost shell of the most electronegative element is :
  • $\ce{2s^22p^5}$
  • B
    $\ce{3s^23p^5}$
  • C
    $\ce{4s^24p^5}$
  • D
    $\ce{5s^25p^5}$

Answer

Correct option: A.
$\ce{2s^22p^5}$
The electronic configuration represents.
$\ce{2s^22p^5} =$ fluorine $=$ most electronegative element.
$\ce{3s^23p^5} =$ chlorine.
$\ce{4s^24p^5} = $ bromine.
$\ce{5s^25p^5} =$ iodine.

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