The emf of a battery is $2\, V$ and its internal resistance is $0.5 \,\Omega$. The maximum power which it can deliver to any external circuit will be ............. $watt$
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(c) ${P_{{\rm{max}}}} = \frac{{{E^2}}}{{4r}} = \frac{{{{(2)}^2}}}{{4 \times 0.5}} = 2\,W$
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