The end $A$ of a rod $AB$ of length $1\,m$ is maintained at $80\,^oC$ and the end $B$ at $0\,^oC.$ The temperature at a distance of $60\,\,c.m.$ from the end $A$ is......... $^oC$
A$16$
B$32$
C$48$
D$64$
Medium
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B$32$
b $\left(\frac{\mathrm{dQ}}{\mathrm{dt}}\right)_{\mathrm{AC}}=\left(\frac{\mathrm{dQ}}{\mathrm{dt}}\right)_{\mathrm{AB}}$
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