The energy and capacity of a charged parallel plate capacitor are $U$ and $C$ respectively. Now a dielectric slab of $\in _r = 6$ is inserted in it then energy and capacity becomes (Assume charge on plates remains constant)
Medium
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$C' = kC\,\,\,\,\,\,\,\,\,U = \frac{1}{2}\,C{V^2}$
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