The energy required to charge a capacitor of $5\,\mu \,F$ by connecting a $d.c$. source of $20\, kV$ is......$kJ$
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(d) $U = \frac{1}{2}C{V^2} = \frac{1}{2}5 \times {10^{ - 6}} \times {(20 \times {10^3})^2} = 1\,kJ$
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