MCQ
The enthalpy change for the conversion of $\frac{1}{2} Cl _2$ (g) to $Cl ^{-}$(aq) is $(-).......$

$kJ\,mol ^{-1}$ (Nearest integer)

Given : $\Delta_{ dis } H _{ Cl _{2(g)}}^{\circ}=240\,kJ\,mol ^{-1}$.

$\Delta_{ eg } H _{ Cl _{(g)}}^{\circ}=-350\,kJ\,mol ^{-1}$,

$\Delta_{ hyd } H _{ Cl i _{( j )}^{\circ}}^{\circ}=-380\,kJ\,mol ^{-1}$

  • A
    $600$
  • B
    $620$
  • C
    $630$
  • $610$

Answer

Correct option: D.
$610$
d
$\frac{1}{2} Cl _{2( g )} \rightarrow Cl _{( g )} \rightarrow Cl _{( g )}^{-} \rightarrow Cl _{( aq .)}^{-}$

$\Delta H ^{\circ}=\frac{1}{2} \times 240+(-350)+(-380)$

$=-610 \text { ans. }$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free