MCQ
The enthalpy of formation of ammonia is $ - 46.0\,kJ\,mo{l^{ - 1}}$. The enthalpy change for the reaction $2N{H_3}(g) \to 2{N_2}(g) + 3{H_2}(g)$ is......$kJ$ $mo{l^{ - 1}}$
- A$46$
- ✓$92$
- C$-23$
- D$-92$
✓
Answer
Correct option: B.
$92$
b
The enthalpy of formation of ammonia is $-46.0\, kJ\, mol ^{-1}$.
The enthalpy of formation of ammonia is $-46.0\, kJ\, mol ^{-1}$.
$1 / 2 N _2( g )+3 / 2 H _2( g ) \rightarrow NH _3( g ) \quad \Delta H =-46.0\, kJ / mol$
Multiply above equation with $2.$
$N _2( g )+3 H _2( g ) \rightarrow 2 NH _3( g ) \Delta H =-46.0 \times 2=-92.0\, kJ / mol$
Reverse above equation
$2 NH _3( g ) \rightarrow N _2( g )+3 H _2( g ) \quad \Delta H =+92.0\, kJ / mol$
The enthalpy change for the reaction $2 NH _3( g ) \rightarrow N _2( g )+3 H _2( g )$ is $92.0 \,KJ mol ^{-1}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Identify the property which does not reflect the periodicity of the elements.
The stability order of the following carbocations is
When $pH$ of a solution decreases, its hydrogen ion concentration
→Which of the following reagents and conditions convert benzene to chloro-benzene :
$2\, gm$ acetic acid and $3\, gm$ sodium acetate are present in $100\, ml$. aqueous solution then what will be the $pH$ of solution if ionisation constant of acetic acid is $1.8 \times 10^{-5}$
→In ${H_2}{O_2}$ molecule, the angle between the two $O -H$ planes is ............. $^o$
→The difference in the oxidation numbers of the two types of sulphur atoms in $\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6$ is :
→Which of the following compounds will show the maximum ‘enol’ content?
Which is not correct
Assuming complete ionisation, the $pH$ of $0.1\,M\,HCl,$ is $1$. The molarity of ${H_2}S{O_4}$ with the same $pH$ is
→