The enthalpy of neutralization of HCN by NaOH is - 12.13 ,kJ ,mo … - Vidyadip

MCQ

The enthalpy of neutralization of $HCN$ by $NaOH$ is $ - 12.13\,kJ\,mo{l^{ - 1}}$. The enthalpy of ionisation of $HCN$ will be....$kJ$

A
$4.519$
B
$45.10$
C
$451.9$
✓
$45.19 $

✓

Answer

Correct option: D.

$45.19 $

(d)$Q = 18.94 \times 0.632 \times 0.998 \times 1000$
$ - 57.4 + x = - 12.13$
$x = 45.2$

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