MCQ
The equation of the tangents drawn at the ends of the major axis of the ellipse $9{x^2} + 5{y^2} - 30y = 0$, are
- A$y = \pm 3$
- B$x = \pm \sqrt 5 $
- ✓$y = 0,\;y = 6$
- DNone of these
==> $9{x^2} + 5({y^2} - 6y + 9) = 45$
==> $\frac{{{x^2}}}{5} + \frac{{{{(y - 3)}^2}}}{9} = 1$
$\because {a^2} < {b^2},$ so axis of ellipse on $y$ - axis.
At $y$ axis, put $x = 0$, so we can obtained vertex.
Then $0 + 5{y^2} - 30y = 0$
$y = 0,\,\,y = 6$
Therefore, tangents of vertex $y = 0,\,\,\,y = 6$.
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