$X \rightleftharpoons 2Y$ and $Z \rightleftharpoons P + Q,$
respectively are in the ratio of $1 : 4.$ If the degree of dissociation of $X$ is $2$ times that of $Z,$ then the ratio of total pressure $(P_1 : P_2)$ at these equilibria is : (Assume degree of dissociation for both reactions are very very small)
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${N_2}{H_4}\left( l \right) + 2{H_2}{O_2}\left( l \right) \to \mathop {{N_2}\left( g \right) + 4{H_2}O\left( l \right);}\limits_{{\Delta_r} H_1^o = - 818\,kJ/mol} $
${N_2}{H_4}\left( l \right) + {O_2}\left( g \right) \to \mathop {{N_2}\left( g \right) + 2{H_2}O\left( l \right);}\limits_{{\Delta _r}H_2^o = - 622\,kJ/mol} $
${H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \to \mathop {{H_2}O\left( l \right);}\limits_{{\Delta _r}H_3^o = - 285\,kJ/mol} $
.......$kJ/mol$