The equivalent capacitance between $A$ and $B$ in the figure is $1\,\mu F$. Then the value of capacitance $C$ is.....$\mu F$
Medium
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(a) From the given figure, total capacitance is
$\frac{1}{1} = \frac{1}{C} + \frac{1}{{(1 + 2.5)}}$ $==>$ $1 = \frac{1}{C} + \frac{1}{{3.5}}$ $==>$ $C = \frac{{3.5}}{{2.5}} = 1.4\,\mu F$
$\frac{1}{1} = \frac{1}{C} + \frac{1}{{(1 + 2.5)}}$ $==>$ $1 = \frac{1}{C} + \frac{1}{{3.5}}$ $==>$ $C = \frac{{3.5}}{{2.5}} = 1.4\,\mu F$
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