The equivalent capacitance between $A$ and $B$ is.......$\mu \,F$
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(d) $\frac{1}{C} = \frac{1}{2} + \frac{1}{1} + \frac{1}{2} = \frac{{1 + 2 + 1}}{2} = \frac{4}{2} = 2$ $==>$ ${C_{AB}} = 0.5\,\mu F$
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