MCQ
The equivalent weight of $MnS{O_4}$ is half its molecular weight when it is converted to
- A$M{n_2}{O_3}$
- ✓$Mn{O_2}$
- C$Mn{O_4}$
- D$MnO_4^{2 - }$
Change of valency $ = 4 - 2 = 2$
$\therefore $ Equivalent weight $ = \frac{M}{2}$.
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