MCQ
The equivalent weight of $MnS{O_4}$ is half its molecular weight when it is converted to
  • A
    $M{n_2}{O_3}$
  • $Mn{O_2}$
  • C
    $Mn{O_4}$
  • D
    $MnO_4^{2 - }$

Answer

Correct option: B.
$Mn{O_2}$
b
(b) $\mathop {Mn}\limits^{ + 2} S{O_4} \to \mathop {Mn}\limits^{ + 4} {O_2}$

Change of valency $ = 4 - 2 = 2$

$\therefore $ Equivalent weight $ = \frac{M}{2}$.

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