MCQ
The exact volumes of $1\, M\, NaOH$ solution required to neutralise $50 \,mL$ of $1 \,M \,H _{3} PO _{3}$ solution and $100\, mL$ of $2 \,M\, H _{3} PO _{2}$ solution, respectively, are :
  • A
    $100 \,mL$ and $100\, mL$
  • B
    $100 \,mL$ and $50\, mL$
  • $100\, mL$ and $200 \,mL$
  • D
    $50\, mL$ and $50 \,mL$

Answer

Correct option: C.
$100\, mL$ and $200 \,mL$
c
$H _{3} PO _{3}+2 NaOH \rightarrow Na _{2} HPO _{3}+2 H _{2} O$

$\begin{array}{ll}50\, ml & 1\, M \\ 1\, M & V =?\end{array}$

$\Rightarrow \frac{ n _{ NaoH }}{ n _{ H _{3} PO _{3}}}=\frac{2}{1}$

$\Rightarrow \frac{1 \times V }{50 \times 1}=\frac{2}{1} \Rightarrow{ V _{ NaOH }=100\, ml }$

$H _{3} PO _{2}+2 NaOH \rightarrow NaH _{2} PO _{3}+ H _{2} O$

$\begin{array}{lc}100\, ml & 1\, M \\ 2\, M & V =?\end{array}$

$\Rightarrow \frac{ n _{ NaoH }}{ n _{ H _{3} PO _{3}}}=\frac{1}{1} \Rightarrow \frac{1 \times V }{2 \times 100}=\frac{1}{1} \Rightarrow V _{ NaOH }=200\, ml$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free