MCQ
The expression $\left(\frac{1}{\sqrt{2}} \hat{i}+\frac{1}{\sqrt{2}} \hat{j}\right)$ is a
  • Unit vector
  • B
    Null vector
  • C
    Vector of magnitude $\sqrt{2}$
  • D
    Scalar

Answer

Correct option: A.
Unit vector
(a) $\vec{P}=\frac{1}{\sqrt{2}} \hat{i}+\frac{1}{\sqrt{2}} \hat{j} \therefore|\vec{P}=\sqrt{\left(\frac{1}{\sqrt{2}}\right)^2+\left(\frac{1}{\sqrt{2}}\right)^2}=1$$\therefore$ lt is a unit vector.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The linear momentum $p$ of a body moving in one dimension varies with time according to the equation $p=a+b t^2$, where $a$ and $b$ are positive constants. The net force acting on the body is
Two magnets $A$ and $B$ are identical in mass, length and breadth but have different magnetic moments. In a vibration magnetometer, if the time period of $B$ is twice the time period of $A$. The ratio of the magnetic moments $M_A / M_B$ of the magnets will be
If the water falls from a dam into a turbine wheel $19.6 \mathrm{~m}$ below, then the velocity of water at the turbine is $\left(g=9.8 \mathrm{~m} / \mathrm{s}^2\right)$
If $m$ is mass of electron, $v$ its velocity, $r$ the radius of stationary circular orbit around a nucleus with charge $Z e$, then from Bohr's first postulate, the kinetic energy $K=\frac{1}{2} m v^2$ of the electron in C.G.S. system is equal to
The kinetic energy possessed by a body of mass $m$ moving with a velocity $v$ is equal to $\frac{1}{2} m v^2$, provided
When a body moves in a circular path, no work is done by the force since,
A suitable unit for gravitational constant is
Two identical coaxial circular loops carry current each circulating in the clockwise direction. If the loops are approaching each other, then
A racing car moving towards a cliff, sounds its horn. The driver observes that the sound reflected from the cliff has a pitch one octave higher than the actual sound of the horn. If $v$ is the velocity of sound, then the velocity of the car is
If the length of a closed organ pipe is $1 \mathrm{~m}$ and velocity of sound is $330 \mathrm{~m} / \mathrm{s}$, then the frequency for the second note is