The figure shows a network of five resistances and two batteries The current through the $15\,V$ battery is .............. $A$
Diffcult
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A battery of internal resistance $4\, ohm$ is connected to the network of resistance as hown. In the order that the maximum power can be delivered to the network, the value of $R$ in ohm should be :-
The current $i_1$ and $i_2$ through the resistors $R_1(=10\,\Omega )$ and ${R_2}\left( { = 30\,\Omega } \right)$ in the circuit diagram with $E_1 = 3\,V$, $E_2 = 3\,V$ and $E_3 = 2\,V$ are respectively
ln the circuit in the figure, if no current flows through the galvanometer when the key $K$ is closed, the bridge is balanced. The balancing condition for bridge is
Suppose the drift velocity $v_d$ in a material varied with the applied electric field $E$ as ${v_d}\, \propto \,\sqrt E $ .Then $V - I$ graph for a wire made of such a material is best given by
Fig. shows rough sketch of meter bridge. $(G)$ deflects zero at length $\ell \, cm$. Now $R_1$ and $R_2$ are interchanged then balancing length increases by $25\, cm$. Find $R_1/R_2$
When a potential difference $V$ is applied across a wire of resistance $R$, it dissipates energy at a rate $W$. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the same supply, the energy dissipation rate will become: