MCQ
The first ionization energy for Li is $5.4 \,eV $ and electron affinity of $Cl$  is $3.61\,eV.$ The $\Delta H$ (in $kJ/mol$) for the reaction $Li(g) + Cl(g) \to L{i^ + } + C{l^ - }$ is (if resulting ions do not combine with each other) $(1\,eV = 1.6 \times {10^{ - 19}}\,J)$
  • A
    $70$
  • B
    $100$
  • $170$
  • D
    $270$

Answer

Correct option: C.
$170$
(c)First ionization potential of $Li = 5.4\,eV$
Electron affinity of $Cl = 3.61\,eV$
We have $\Delta H = I.P. - E.A.$
$ = 5.4 - 3.61 = 1.80\,eV = 1.80 \times 1.6 \times {10^{ - 22}}\,kJ$
$\Delta H = 2.86 \times {10^{ - 22}}\,kJ,$
for $ 1\,mol$  Avogadro’s number $ = 6.02 \times {10^{23}}$.
$\Delta H = 2.86 \times {10^{ - 22}} \times 6.02 \times {10^{23}} = 170\,kJ/mole.$

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