MCQ
The first overtone of a stretched wire of given length is $320 Hz$. The first harmonic is .... $Hz$
- A$320$
- ✓$160$
- C$480$
- D$640$
So, frequency of first harmonic ${n_1} = \frac{{{n_2}}}{2} = \frac{{320}}{2} = 160Hz$
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