The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.
$(a.)\frac{2}{12}$ $(b.)\frac{3}{15}$ $(c.)\frac{8}{50}$ $(d.)\frac{16}{100}$ $(e.)\frac{10}{60}$ $(f.)\frac{15}{75}$ $(g.)\frac{12}{60}$ $(h.)\frac{16}{96}$ $(i.)\frac{12}{75}$ $(j.)\frac{12}{72}$ $(k.)\frac{3}{18}$ $(l.)\frac{4}{25}$
✓
Answer
$(a.)$ In this question, we have,
$\frac{2}{12}=\frac{1 \times 2}{6 \times 2}=\frac{1}{6}$
$(b.)$ In this question, we have,
$\frac{3}{15}=\frac{1 \times 3}{5 \times 3}=\frac{1}{5}$
$(c.)$ In this question, we have,
$\frac{8}{50}=\frac{4 \times 2}{25 \times 2}=\frac{4}{25}$
$(d.)$ In this question, we have,
$\frac{16}{100}=\frac{4 \times 4}{25 \times 4}=\frac{4}{25}$
$(e.)$ In this question, we have,
$\frac{10}{60}=\frac{1 \times 10}{6 \times 10}=\frac{1}{6}$
$(f.)$ In this question, we have,
$\frac{15}{75}=\frac{1 \times 15}{5 \times 15}=\frac{1}{5}$
$(g.)$ In this question, we have,
$\frac{12}{60}=\frac{1 \times 12}{5 \times 12}=\frac{1}{5}$
$(h.)$ In this question, we have,
$\frac{16}{96}=\frac{1 \times 16}{6 \times 16}=\frac{1}{6}$
$(i.)$ In this question, we have,
$\frac{12}{75}=\frac{4 \times 3}{25 \times 3}=\frac{4}{25}$
$(j.)$ In this question, we have,
$\frac{12}{72}=\frac{1 \times 12}{6 \times 12}=\frac{1}{6}$
$(k.)$ In this question, we have,
$\frac{3}{18}=\frac{1 \times 3}{6 \times 3}=\frac{1}{6}$
$(l.)$ In this question, we have,
$\frac{4}{25}$
From above, we see that, there are three groups of equivalent fractions:
$\frac{1}{6} = (a), (e), (h), (j)$ and $(k)$
$\frac{1}{5} = (b), (f)$ and $(g)$
$ \frac{4}{25} = (c), (d), (i)$ and $(l)$
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