Download App

The s-block Elements — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryThe s-block Elements1 Mark
MCQ
The formula of soda ash is :
  • ✓
    $ \mathrm{NaHCO}_3 \cdot 10 \mathrm{H}_2 \mathrm{O} $
  • B
    $\mathrm{Na}_2 \mathrm{CO}_3 \cdot 2 \mathrm{H}_{2 \mathrm{O}} $
  • C
    $ \mathrm{Na}_2 \mathrm{CO}_3 \cdot \mathrm{H}_2 \mathrm{O} $
  • D
    $ \mathrm{Na}_2 \mathrm{CO}_3 $
✓

Answer

Correct option: A.
$ \mathrm{NaHCO}_3 \cdot 10 \mathrm{H}_2 \mathrm{O} $
On heating washing soda, it loses its water of crystallization. Above $373 K$, it becomes completely anhydrous white powder called soda ash.
$\text{Na}_2\text{CO}_3.10\text{H}_2\text{O}\xrightarrow{>373\text{K}\ \ }\text{Na}_2\text{CO}_3\\\text{Washing soda}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Soda Ash}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from The s-block Elements→The s-block Elements — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Which of the following has largest ionic radius
→
The absolute configuration of the compound is
→
First three ionisation energies (in $kJ/mol$) of three representative elements are  given below

Element $IE_1$ $IE_2$ $IE_3$
$P$ $495.8$ $4562$ $6910$
$Q$ $737.7$ $1451$ $7733$
$R$ $577.5$ $1817$ $2745$

Then incorrect option is

→
The ratio of difference between $1^{st}$ and $2^{nd}$ Bohr orbits energy to that between  $2^{nd}$ and $3^{rd}$ orbits energy is
→
Sulphur has highest oxidation state in
→
The absolute configuration of given is :
→
Many elements have non-integral atomic masses because :
→
Calculate the $\lambda$ of $CO_2$ molecule moving with a velocity $440\, m/s.$
→
Which of the following alkanes can be synthesized by the Wurtz reaction in good yield?
→
The mass of $BaC{O_3}$ produced when excess $C{O_2}$ is bubbled through a solution of $0.205$ mol $Ba{(OH)_2}$ is ............ $\mathrm{gm}$
→