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Trigonometric Functions — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsTrigonometric Functions2 Marks
MCQ
The general solution of the equation $4 \cos ^2 x+6 \sin ^2 x=5$, is
  • A
    $x= n \pi \pm \frac{\pi}{2}$
  • ✓
    $x=n \pi \pm \frac{\pi}{4}$
  • C
    $x= n \pi \pm \frac{3 \pi}{2}$
  • D
    $x=n \pi \pm \frac{3 \pi}{4}$
✓

Answer

Correct option: B.
$x=n \pi \pm \frac{\pi}{4}$
(B) $4 \cos ^2 x+6 \sin ^2 x=5$
$\begin{array}{l}\therefore 4+2 \sin ^2 x=5 \\ \therefore \sin ^2 x=\frac{1}{2}=\sin ^2 \frac{\pi}{4} \Rightarrow x= n \pi \pm \frac{\pi}{4}\end{array}$

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