CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsSurface Tension1 Mark
MCQ
The graph between $\sqrt{E}$ and $\frac{1}{p}$ is $(E=$ kinetic energy and $p=$ momentum)
A
B
✓
D
✓
Answer
Correct option: C.
(c) $P=\sqrt{2 m E}$ it is clear that $P \propto \sqrt{E}$So the graph between $P$ and$\sqrt{E}$ will be straight line.but graph between $\frac{1}{P}$ and $\sqrt{E}$ will be hyperbola
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