The heat developed in an electric wire of resistance $R$ by a current $I$ for a time $t$ is
A$\frac{{{I^2}Rt}}{{4.2}}cal$
B$\frac{{{I^2}t}}{{4.2R}}cal$
C$\frac{{{I^2}R}}{{4.2\,t}}cal$
D$\frac{{Rt}}{{4.2\,{I^2}}}cal$
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A$\frac{{{I^2}Rt}}{{4.2}}cal$
a (a) $P=\frac{E}{t}$
$E=p \times t$
$P=\frac{v^{2}}{R}=I^{2} R$
$E=I^{2} R \times t$ Jonle
$'J=\frac{1}{4.2}cal$
$E=\frac{I^{2} R\times t}{4.2} cal$
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In the circuit shown $E, F, G$ and $H$ are cells of $\mathrm{e.m.f.}$ $2\,V, 1\,V, 3\,V$ and $1\,V$ respectively and their internal resistances are $2\,\Omega , 1\,\Omega , 3\,\Omega$ and $1\,\Omega$ respectively.
.............. $A$ the current flowing through the resistance $R_2$ of the circuit shown in fig if the resistance are equal to $R_1 = 20\ \Omega, R_2 = 30 \ \Omega$ and $R_3 = 60 \ \Omega$ and potentials of points $1, 2$ and $3$ are equal to $V_1= 20\, V,$ $V_2 = 30\ V$ and $V_3 = 60\ V$