MCQ
The heat of neutralization of $HCl$ by $NaOH$ under certain condition is $-55.9\,\, kJ$ and that of $HCN$ by $NaOH$ is $-12.1\,\, kJ$. the heat of ionization of $HCN$ is .............. $\mathrm{kJ \,mol}^{-1}$
- A$ - 68$
- B$ - 43.8$
- C$68$
- ✓$43.8$
