The height of liquid column in a $U$ tube is $0.3$ meter. If the liquid in one of the limbs is depressed and then released, then the time period of liquid column will be $.......\,sec$
A$0.11$
B$19$
C$1.1$
D$2$
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C$1.1$
c (c)
$T =2 \pi \sqrt{\frac{ h }{ g }}$ or $T =2 \times 3.14 \times \sqrt{\frac{0.3}{9.8}}=1.1 sec$
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