MCQ
The hydrocarbon which can react with sodium in liquid ammonia is
- A$CH_3CH_2CH_2C \equiv CCH_2CH_2CH_3$
- ✓$CH_3CH_2C \equiv CH$
- C$CH_3CH \equiv CHCH_3$
- D$CH_3CH_2C \equiv CCH_2CH_3$
Hence $C H_{3} C H_{2} C \equiv C H$ is the correct option.
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| List $I$ (Mixture) | List $II$ (Separation Technique) |
| $A$ $CHCl _3+ C _6 H _5 NH _2$ | $I$ Steam distillation |
| $B$ $C _6 H _{14}+ C _5 H _{12}$ | $II$ Differential extraction |
| $C$ $C _6 H _5 NH _2+ H _2 O$ | $III$ Distillation |
| $D$ Organic compound in $H _2 O$ | $IV$ Fractional distillation |