The intensity level due to two waves of the same frequency in a given medium are $1\, bel$ and $5\, bel$. Then the ratio of amplitudes is
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(d) By using $L = {\log _{10}}\frac{I}{{{I_0}}}$
${L_2} - {L_1} = {\log _{10}}\frac{{{I_2}}}{{{I_0}}} - {\log _{10}}\frac{{{I_1}}}{{{I_0}}}$
$5 - 1 = {\log _{10}}\frac{{{I_2}}}{{{I_1}}}$
==> $4 = {\log _{10}}\frac{{{I_2}}}{{{I_1}}}$
==> $\frac{{{I_2}}}{{{I_1}}} = {10^4}$
==> $\frac{{a_2^2}}{{a_1^2}} = {10^4}$
==> $\frac{{{a_2}}}{{{a_1}}} = \frac{{{{10}^2}}}{1}$
==> $\frac{{{a_1}}}{{{a_2}}} = \frac{1}{{{{10}^2}}}$
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