The internal and external radii of a hollow cylinder are measured with the help of a vernier callipers.Their values are $(4.23 \pm 0.01)\,\,cm$ and $(3.87 \pm 0.01)\,\,cm,$ respectively. The thickness of the wall of the cylinder is
A$(0.36 \pm 0.02)\,\,cm$
B$(0.18 \pm 0.02)\,\,cm$
C$(0.36 \pm 0.01)\,\,cm$
D$(0.18 \pm 0.01)\,\,cm$
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A$(0.36 \pm 0.02)\,\,cm$
a Thickness $(t)\,\,= [(4.23 -3.87) \pm (0.01 + 0.01)]\,\,cm$
$= [0.36 \pm 0.02]$
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