MCQ
The ionic product of water at ${25\,^o}C$ is ${10^{ - 14}}.$ The ionic product at ${90\,^o}C$ will be
  • A
    $1 \times {10^{ - 20}}$
  • $1 \times {10^{ - 12}}$
  • C
    $1 \times {10^{ - 14}}$
  • D
    $1 \times {10^{ - 16}}$

Answer

Correct option: B.
$1 \times {10^{ - 12}}$
(b) When increasing the temperature the value of ionic product also increases.

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