MCQ
The kinetic energy of translation of the molecules in 50 g of $\mathrm{CO}_{2}$ gas at $17^{\circ} \mathrm{C}$ is :
- A3986.3 J
- B4102.8 J
- C4205.5 J
- D3582.7 J
✓
Answer
B.
$(\mathrm{KE})_{\text {Translational }}=\left[\frac{3}{2} \mathrm{KT}\right] \times$ no. of molecule
No. of molecule $=\left[\frac{50}{44} \times 6.023 \times 10^{23}\right]$
$(\mathrm{KE})_{\text {Translational }}=4108.644 \mathrm{~J}$
$(\mathrm{KE})_{\text {Translational }}=\left[\frac{3}{2} \mathrm{KT}\right] \times$ no. of molecule
No. of molecule $=\left[\frac{50}{44} \times 6.023 \times 10^{23}\right]$
$(\mathrm{KE})_{\text {Translational }}=4108.644 \mathrm{~J}$
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