MCQ
The Lassaigne’s extract is boiled with dil. $HNO_3$ before testing for halogens because
- ASilver halides are soluble in $HNO_3$
- ✓$Na_2S$ and $NaCN$ are decomposed by $HNO_3$
- C$Ag_2S$ is soluble in $HNO_3$
- D$AgCN$ is soluble in $HNO_3$
$N{a_2}S + 2AgN{O_3} \to 2NaN{O_3} + \mathop {A{g_2}S}\limits_{Black} \downarrow $
$NaCN + AgN{O_3} \to NaN{O_3} + \mathop {AgCN}\limits_{White} \downarrow $
$NaCl + AgN{O_3} \to NaN{O_3} + \mathop {AgCl}\limits_{white} \downarrow $
$N{a_2}S + 2HN{O_3}\xrightarrow{{boil}}2NaN{O_3} + {H_2}S \uparrow $
$NaCN + HN{O_3}\xrightarrow{{boil}}NaN{O_3} + HCN \uparrow $
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Reason : Benzene is a solvent for the Friedel- Craft's alkylation of bromobenzene.
$(a)$ Polarising power of cation
$(b)$ Extent of distortion of anion
$(c)$ Polarisability of the anion
$(d)$ Polarising power of anion

