The length of the resistance wire is increased by $10\%$. What is the corresponding change in the resistance of wire ................ $\%$
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$\frac{{{R_1}}}{{{R_2}}} = {\left( {\frac{{{l_1}}}{{{l_2}}}} \right)^2},$ If ${l_1} = 100$ then $l_2 = 110$
$ \Rightarrow $ $\frac{{{R_1}}}{{{R_2}}} = {\left( {\frac{{100}}{{110}}} \right)^2}$ $ \Rightarrow $ ${R_2} = 1.21\,{R_1}$
$\%$ change $\frac{{{R_2} - {R_1}}}{{{R_1}}} \times 100 = 21\% $
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