The length of wire becomes $l_1$ and $l_2$ when $100\,N$ and $120\,N$ tensions are applied respectively. If $10l_2=11l_1$, the natural length of wire will be $\frac{1}{x} l_1$. Here the value of $x$ is ........
  • A$8$
  • B$2$
  • C$6$
  • D$4$
JEE MAIN 2023, Medium
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