An aluminium rod with Young's modulus Y =7.0 times 10^{10} N / m ^2 undergoes elastic strain of 0.04 %. The energy per unit volume

Q: An aluminium rod with Young's modulus $Y =7.0$ $\times 10^{10} N / m ^2$ undergoes elastic strain of $0.04 \%$. The energy per unit volume stored in the rod in SI unit is:

a $Y =7 \times 10^{10}\,N / m ^2$ $\text { Strain }=\frac{0.04}{100}$ $\text { Energy }=\frac{1}{2}\left(\frac{ YA }{l}\right) \Delta x ^2$ $\text { Energy }=\frac{1}{2} YA \left(\frac{\Delta x }{l}\right)^2 \times l$ $\frac{ E }{ V }=\frac{1}{2} \times Y \times \operatorname{strain}{ }^2$ $=\frac{1}{2} \times 7 \times 10^{10} \times \frac{0.04 \times 0.04}{10^4}=56 \times 10^2$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

An aluminium rod with Young's modulus $Y =7.0$ $\times 10^{10} N / m ^2$ undergoes elastic strain of $0.04 \%$. The energy per unit volume stored in the rod in SI unit is:

A$5600$
B$8400$
C$2800$
D$11200$

JEE MAIN 2023, Easy

STD 11 Science
JEE
STD 11- 8. mechanical properties of solids
Physics

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