When a uniform wire of radius $r$ is stretched by a $2kg$ weight, the increase in its length is $2.00\, mm$. If the radius of the wire is $r/2$ and other conditions remain the same, the increase in its length is .......... $mm$
A$2.00$
B$4.00$
C$6.00$
D$8.00$
Medium
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D$8.00$
d (d) $l = \frac{{FL}}{{\pi {r^2}Y}}\therefore l \propto \frac{1}{{{r^2}}}$ $(F,L$ and $Y$ are constant$)$
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