MCQ
The linear equation 3x - 5y = 15 has
- Ano solution
- Binfinitely many solutions
- Ca unique solution
- Dtwo solutions
✓
Answer
(b) infinitely many solutions
Explanation:
Given linear equation: $3 x-5 y=15 Or , x=\frac{5 y+15}{3}$
When $y=0, x=\frac{15}{3}=5$
When $y=3, x=\frac{30}{3}=10$
When $y=-3, x=\frac{0}{3}=0$
Plot the points A(5,0) , B(10,3) and C(0,−3). Join the points and extend them in both the directions.
We get infinite points that satisfy the given equation.
Hence, the linear equation has infinitely many solutions.
Explanation:
Given linear equation: $3 x-5 y=15 Or , x=\frac{5 y+15}{3}$
When $y=0, x=\frac{15}{3}=5$
When $y=3, x=\frac{30}{3}=10$
When $y=-3, x=\frac{0}{3}=0$
| xx | 5 | 10 | 0 |
| yy | 0 | 3 | -3 |
We get infinite points that satisfy the given equation.
Hence, the linear equation has infinitely many solutions.
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