- ✓The current passing through it
- BThe voltage across it
- CThe power through it
- DAll
The magnetic field produced by a current $-$ carrying wire at a given point depends directly on the current passing through it.
Therefore, if there is a circular coil having n turns, the field produced is n times as large as that produced by a single turn.
This is because the current in each circular turn has the same direction, and the field due to each turn then just adds up.
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$(i)$ $6.563 \times {10^{ - 19}}C$ $ (ii)$ $8.204 \times {10^{ - 19}}C$
$(iii)$ $11.50 \times {10^{ - 19}}C$ $ (iv)$ $13.13 \times {10^{ - 19}}C$
$(v)$ $16.48 \times {10^{ - 19}}C$ $ (vi)$ $18.09 \times {10^{ - 19}}C$
From this data the value of the elementary charge $(e)$ was found to be
In the given nuclear reaction, the approximate amount of energy released will be $.....\,MeV$
$\text { [Given, mass of }{ }_{92}^{238} A =238.05079 \times 931.5\,MeV / c ^2$
$\text { mass of }{ }_{90}^{234} B =234.04363 \times 931.5\,MeV / c ^2$
$\text { mass of } \left.{ }_2^4 D =4.00260 \times 931.5\,MeV / c ^2\right]$
