Download App
The magnetic induction due to an infinitely long straight wire carrying a current $i$ at a distance $r$ from wire is given by
  • A$|B|\, = \left( {\frac{{{\mu _0}}}{{4\pi }}} \right)\frac{{2i}}{r}$
  • B$|B|\, = \left( {\frac{{{\mu _0}}}{{4\pi }}} \right)\frac{r}{{2i}}$
  • C$|B|\, = \left( {\frac{{4\pi }}{{{\mu _0}}}} \right)\frac{{2i}}{r}$
  • D$|B|\, = \left( {\frac{{4\pi }}{{{\mu _0}}}} \right)\frac{r}{{2i}}$
Easy
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Download App

Similar Questions

  • 1
    An electron is projected with velocity $v_0$ in a uniform electric field $E$ perpendicular to the field. Again it is projetced with velocity $v_0$ perpendicular to a uniform magnetic field $B/$ If $r_1$ is initial radius of curvature just after entering in the electric field and $r_2$ is initial radius of curvature just after entering in magnetic field then the ratio $r_1:r_2$ is equal to 
    View Solution
  • 2
    A straight wire $AB$ of mass $40\,g$ and length $50\,cm$ is suspended by a pair of flexible leads in uniform magnetic field of magnitude $0.40\,T$ as shown in the figure. The magnitude of the current required in the wire to remove the tension in the supporting leads is ...........$A$. (Take $g=10\,ms ^{-2}$ ).
    View Solution
  • 3
    The magnetic field due to a current carrying square loop of side a at a point located symmetrically at a distance of $a/2$ from its centre (as shown is)
    View Solution
  • 4
    A square loop of side $l$ is kept in a uniform magnetic field $B$ such that its plane makes an angle $\alpha$ with $\vec{B}$. The loop carries a current $i$. The torque experienced by the loop in this position is
    View Solution
  • 5
    An electron enters the space between the plates of a charged capacitor as shown. The charge density on the plate is $\sigma $. Electric intensity in the space between the plates is $E$. A uniform magnetic field $B$ also exists in that space perpendicular to the direction of $E$. The electron moves perpendicular to both $\vec E$ and $\vec B$ without any change in direction. The time taken by the electron to travel a distance $\ell $ is the space is
    View Solution
  • 6
    Two mutually perpendicular insulated conducting wires carrying equal currents $I$, intersect at origin. Then the resultant magnetic induction at point $P(2m, 3m)$ will be
    View Solution
  • 7
    An electron and a proton are moving on straight parallel paths with same velocity. They enter a semi-infinite region of uniform magnetic field perpendicular to the velocity. Which of the following statement$(s)$ is/are true?

    $(A)$ They will never come out of the magnetic field region.

    $(B)$ They will come out travelling along parallel paths.

    $(C)$ They will come out at the same time.

    $(D)$ They will come out at different times.

    View Solution
  • 8
    Statement $-1$ : Ampere law can be used to find magnetic field due to finite length of a straight current carrying wire.

    Statement $-2$ : The magnetic field due to finite length of a straight current carrying wire is symmetric about the wire.

    View Solution
  • 9
    A charged particle enters a magnetic field $H$ with its initial velocity making an angle of $45^\circ $ with $H$. The path of the particle will be
    View Solution
  • 10
    $STATEMENT-1$  A vertical iron rod has a coil of wire wound over it at the bottom end. An alternating current flows in the coil. The rod goes through a conducting ring as shown in the figure. The ring can float at a certain height above the coil. Because

    $STATEMENT- 2$ In the above situation, a current is induced in the ring which interacts with the horizontal component of the magnetic field to produce an average force in the upward direction.

    View Solution