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8. mechanical properties of solids — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics8. mechanical properties of solids1 Mark
MCQ
The mass and length of a wire are $M$ and $L$ respectively. The density of the material of the wire is $d$. On applying the force $F$ on the wire, the increase in length is $l$, then the Young's modulus of the material of the wire will be
  • A
    $\frac{{Fdl}}{{Ml}}$
  • B
    $\frac{{FL}}{{Mdl}}$
  • C
    $\frac{{FMl}}{{dl}}$
  • ✓
    $\frac{{Fd{L^2}}}{{Ml}}$
✓

Answer

Correct option: D.
$\frac{{Fd{L^2}}}{{Ml}}$
d
(d) $Y = \frac{F}{A}\frac{L}{l}$ $ = \frac{{Fd{L^2}}}{{Ml}}$

As $M =$ volume $\times$ density $ = A \times L \times d$ $\therefore$ $A = \frac{M}{{Ld}}$

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