MCQ
The mass of $Mg_3N_2$ produced if $48\, gm$ of $Mg$ metal is reacted with $34\, gm\, NH_3$ gas is
$Mg + NH_3 \to Mg_3N_2 + H_2$
  • $\frac{200}{3} \,gm$
  • B
    $\frac{100}{3} \,gm$
  • C
    $\frac{400}{3} \,gm$
  • D
    $\frac{150}{3} \,gm$

Answer

Correct option: A.
$\frac{200}{3} \,gm$
a
$\mathop {\mathop {3{\text{Mg}}}\limits_{3\,{\text{mol}}} }\limits_{(72\,g)}  + \mathop {\mathop {2{\text{N}}{{\text{H}}_3}}\limits_{2\,mol} }\limits_{(34\,g)}  \to \mathop {\mathop {{\text{M}}{{\text{g}}_3}{{\text{N}}_2}}\limits_{1\,mol} }\limits_{(100\,g)}  + 3{{\text{H}}_2}$

$(L. R.)$

$72 \,g\, Mg$ will produce $\mathrm{Mg}_{3} \mathrm{N}_{2}=100 \,\mathrm{g}$

$48\, \mathrm{g} \,\mathrm{Mg} \text { will produce } \mathrm{Mg}_{3} \mathrm{N}_{2} =\frac{100}{72} \times 48 $

$=\frac{200}{3} \,\mathrm{g} $

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