The maximum acceleration of $5\, kg$ block ...... $m/s^2$
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From $FBD$ of $5\, kg$ mass,
Friction force to the right due to $F$ is $f_{1}=0.1 \times 10 \times 10=10 N$
Friction force to the left due to $F$ is $f_{1}=0.1 \times(10+5) \times 10=45 N$
As $10 \mathrm{N}<45 \mathrm{N},$ the $5 \mathrm{kg}$ block will not move.
Therefore its acceleration is $0 m / s^{2}$
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