The mean free path for a gas, with molecular diameter d and numbe… - Vidyadip

MCQ

The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as :

A
$\frac{1}{\sqrt{2} n ^{2} \pi^{2} d ^{2}}$
B
$\frac{1}{\sqrt{2} n \pi d }$
✓
$\frac{1}{\sqrt{2} n \pi d ^{2}}$
D
$\frac{1}{\sqrt{2} n ^{2} \pi d ^{2}}$

✓

Answer

Correct option: C.

$\frac{1}{\sqrt{2} n \pi d ^{2}}$

c
Mean free path for a gas sample

$\lambda_{ m }=\frac{1}{\sqrt{2} \pi d ^{2} n }$

where $d$ is diameter of a gas molecule and $n$ is molecular density

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